Z^2+(2*i*z)+i=0

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Solution for Z^2+(2*i*z)+i=0 equation:


Simplifying
Z2 + (2i * z) + i = 0

Multiply i * z
Z2 + (2iz) + i = 0

Reorder the terms:
Z2 + i + (2iz) = 0

Solving
Z2 + i + (2iz) = 0

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-1i' to each side of the equation.
Z2 + i + -1i + (2iz) = 0 + -1i

Combine like terms: i + -1i = 0
Z2 + 0 + (2iz) = 0 + -1i
Z2 + (2iz) = 0 + -1i
Remove the zero:
Z2 + (2iz) = -1i

Add '(-2iz)' to each side of the equation.
Z2 + (2iz) + (-2iz) = -1i + (-2iz)

Combine like terms: (2iz) + (-2iz) = 0
Z2 + 0 = -1i + (-2iz)
Z2 = -1i + (-2iz)

Simplifying
Z2 = -1i + (-2iz)

Reorder the terms:
Z2 + i + (2iz) = -1i + i + (-2iz) + (2iz)

Combine like terms: -1i + i = 0
Z2 + i + (2iz) = 0 + (-2iz) + (2iz)
Z2 + i + (2iz) = (-2iz) + (2iz)

Combine like terms: (-2iz) + (2iz) = 0
Z2 + i + (2iz) = 0

The solution to this equation could not be determined.

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